To find the height of the infant son, you need to multiply the basketball player's height by \( \frac{1}{4} \).
The height of the basketball player is \( 6 \frac{2}{3} \) feet, which can be converted to an improper fraction.
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Convert \( 6 \frac{2}{3} \) to an improper fraction: \[ 6 \frac{2}{3} = 6 \times 3 + 2 = 18 + 2 = 20 \text{ (numerator)} \] So, \( 6 \frac{2}{3} = \frac{20}{3} \).
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Now, multiply \( \frac{20}{3} \) by \( \frac{1}{4} \): \[ \frac{20}{3} \times \frac{1}{4} = \frac{20 \times 1}{3 \times 4} = \frac{20}{12} \]
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Simplify \( \frac{20}{12} \): \[ \frac{20}{12} = \frac{5}{3} \text{ (by dividing both the numerator and denominator by 4)} \]
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Convert \( \frac{5}{3} \) back to a mixed number: \[ \frac{5}{3} = 1 \frac{2}{3} \text{ feet} \]
Thus, the height of the basketball player's son is 1 \(\frac{2}{3}\) feet.
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