AP and CQ are perpendicular to BC and AB respectively. If AP : CQ = 3 : 4, the the numerical value of sin A/ sin C.

Answer 1

since ∠B is common to ∆s APB and CQB, and both are right triangles, then they are similar. That is,

AP/CQ = AB/BC = 3/4

Now using the law of sines,

sinA/sinC = BC/AB = 4/3