For a 95% confidence interval, 95% of the sample lie within (μ - 1.96� σ/√n) and (μ + 1.96 σ/√n).
Thus the width of the interval is: 3.92 σ/√n
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So we need to find: n = (3.92 σ/ 6%)²
To do this we need to know (or estimate) the standard deviation (σ).
Any ideas please?
Simple random sample of voters will be taken in a large state. Researchers will construct an approximate 95% confidence interval for the percent of the state¢s voters who will vote for Candidate A. Find the minimum sample size needed to ensure that the width of the interval (right end minus left end) is at most 6%.
Thank you.
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