Even if you can't solve the equations, you can always plug in the choices to see which works. Algebraically, we need
x^2 + 3x - 4 = 2x + 2
x^2 + x - 6 = 0
(x+3)(x-2) = 0
x = -3 or 2
y = 2x+2 = -4 or 6
so, (b)
Any help would be appreciated. Thank you.
What are the solutions of the system?
y = x2 + 3x – 4
y = 2x + 2
Options:
(–3, 6) and (2, –4)
(–3, –4) and (2, 6)
(–3, –4) and (–2, –2)
no solution
1 answer