If you want algebraic area, it is zero, since the sinx curve is above cosx just as much as it is below. See
http://www.wolframalpha.com/input/?i=plot+sinx,cosx
The geometric area is just twice the area on the interval [-3π/4,π/4], or
a = 2∫[-3π/4,π/4] cosx-sinx dx = 4√2
Actually, due to symmetry, the area is also just
4∫[-π/4,π/4] cosx-sinx dx
If you try to integrate on the whole interval [-π/4,3π/4] you get zero.
Any help will be appreciated!
Find the area of the region between x=-3pi/4 and 5pi/4 in the graph enclosed by f(x)=sinx and g(x)=cosx
Thank you!
2 answers
Thank you so much for your time!!