Antonio and Candice had a race. Their distances past a particular landmark as the race progressed can be represented by linear functions and are shown in the table of values and graph below. Which statement is true regarding Antonio and Candice’s race?

Antonio’s Distance Past the Landmark
Time (seconds)
8
12
16
20
24
Distance (meters)
29
41
53
65
77

A graph titled Candice's Distance Past the Landmark has time (seconds) on the x-axis, and Distance (meters) on the y-axis. A line goes through points (5, 22), (10, 42), (15, 62) and (20, 82).
Antonio had a head start of 1 meter.
Antonio had a head start of 3 meters.
Candice had a head start of 1 meter.
Candice had a head start of 3 meters.

1 answer

To determine the correct statement regarding Antonio and Candice's race, we need to analyze the information given.

Antonio's Data Analysis:

From the table, we can observe Antonio's distance at various times:

  • At 8 seconds: 29 meters
  • At 12 seconds: 41 meters
  • At 16 seconds: 53 meters
  • At 20 seconds: 65 meters
  • At 24 seconds: 77 meters

We can calculate the slope (rate of distance per second) of Antonio's movement. The difference in distance over the difference in time gives:

  • From 8 seconds (29m) to 12 seconds (41m): \( \text{Distance change} = 41 - 29 = 12 \) meters \( \text{Time change} = 12 - 8 = 4 \) seconds

    Rate = \( \frac{12}{4} = 3 \) meters/second

This rate remains consistent throughout, indicating that Antonio runs at a constant speed of 3 meters per second.

Candice's Data Analysis:

For Candice, we have points through which a line passes:

  • (5, 22)
  • (10, 42)
  • (15, 62)
  • (20, 82)

Let's calculate the distance Candice covers per second:

From (5, 22) to (10, 42):

  • Distance change: \( 42 - 22 = 20 \) meters
  • Time change: \( 10 - 5 = 5 \) seconds

Rate = \( \frac{20}{5} = 4 \) meters/second.

This indicates that Candice is moving at a speed of 4 meters per second.

Head Start Calculation:

Now, to determine who had a head start, we need to compare their distances at the same time.

Let's find the distance that Candice would have covered at 8 seconds:

Using Candice’s speed of 4 meters/second:

Distance at 8 seconds = \( 4 \times 8 = 32 \) meters.

At 8 seconds, Antonio has traveled 29 meters. Thus, Candice is already ahead:

  • Candice Distance (8 seconds): 32 meters
  • Antonio Distance (8 seconds): 29 meters

This indicates that Candice had a head start of:

\( 32 - 29 = 3 \) meters.

Conclusion:

Candice had a head start of 3 meters, so the correct statement is:

Candice had a head start of 3 meters.