To solve this problem, we can use the formula for exponential decay:
N(t) = N₀ * (1/2)^(t / h)
Where:
- N(t) represents the remaining amount of antinium-226 at time t
- N₀ represents the initial amount of antinium-226
- h represents the half-life of antinium-226
In this case, N₀ = 80 mg, t = 87 hours, and h = 29 hours. Plugging these values into the formula, we get:
N(87) = 80 * (1/2)^(87 / 29)
Simplifying the exponent, we have:
N(87) ≈ 80 * (1/2)^3 ≈ 80 * (1/8) ≈ 10 mg
Therefore, approximately 10 mg of antinium-226 will remain after 87 hours.
So the answer is 10 mg.
Antinium-226 has a half life of 29 hours. If 80 mg of antinium-226 disintegrates over a period of 87 hours, how many mg of antinuim– 226 will remain?
7.25 mg
10 mg
21.75 mg
20 mg
1 answer