Question

🩹Anthony wants to know the average daily high temperatures in his town during the summer. He chose two random samples of 10 consecutive days and recorded the daily high temperatures. The daily high temperatures in Fahrenheit are as follows. Sample 1: 78 82 85 87 90 85 79 86 91 88 Sample 2: 81 79 80 86 89 92 82 88 84 87 Find the mean daily high temperatures of each sample and calculate the difference between these mean daily high temperatures. (2 points) The mean daily high temperature of Sample 1 is °. The mean daily high temperature of Sample 2 is °. The mean daily high temperatures of the two samples differ by °.

Answer 1

To find the mean daily high temperature of each sample, we add up all the temperatures and divide by the total number of temperatures in each sample.

For Sample 1:
(78 + 82 + 85 + 87 + 90 + 85 + 79 + 86 + 91 + 88) / 10 = 865 / 10 = 86.5

So, the mean daily high temperature of Sample 1 is 86.5°F.

For Sample 2:
(81 + 79 + 80 + 86 + 89 + 92 + 82 + 88 + 84 + 87) / 10 = 848 / 10 = 84.8

So, the mean daily high temperature of Sample 2 is 84.8°F.

The difference between these mean daily high temperatures is:
86.5 - 84.8 = 1.7

Therefore, the mean daily high temperatures of the two samples differ by 1.7°F.

Answer 2

ARE YOU SURE

Answer 3

Let's recalculate the mean daily high temperatures for both samples to ensure accuracy.

For Sample 1:
(78 + 82 + 85 + 87 + 90 + 85 + 79 + 86 + 91 + 88) / 10 = 861 / 10 = 86.1

So, the mean daily high temperature of Sample 1 is 86.1°F.

For Sample 2:
(81 + 79 + 80 + 86 + 89 + 92 + 82 + 88 + 84 + 87) / 10 = 848 / 10 = 84.8

So, the mean daily high temperature of Sample 2 is 84.8°F.

The difference between these mean daily high temperatures is:
86.1 - 84.8 = 1.3

Therefore, the mean daily high temperatures of the two samples differ by 1.3°F.