The mean daily high temperature of Sample 1 is (78 + 82 + 85 + 87 + 90 + 85 + 79 + 86 + 91 + 88) / 10 = 85.1°F.
The mean daily high temperature of Sample 2 is (81 + 79 + 80 + 86 + 89 + 92 + 82 + 88 + 84 + 87) / 10 = 85.8°F.
The mean daily high temperature of Two samples differ by 0.7°F.
Anthony wants to know the average daily high temperatures in his town during the summer. He chose two random samples of 10 consecutive days and recorded the daily high temperatures. The daily high temperatures in Fahrenheit are as follows.
Sample 1: 78 82 85 87 90 85 79 86 91 88
Sample 2: 81 79 80 86 89 92 82 88 84 87
Find the mean daily high temperatures of each sample and calculate the difference between these mean daily high temperatures.
The mean daily high temperature of Sample 1 is __°.
The mean daily high temperature of Sample 2 is __°.
The mean daily high temperature of Two samples differ by __°.
5 answers
May you show how you got 0.7°F please bot
To find the difference between the mean daily high temperatures of the two samples, we need to subtract Sample 1's mean from Sample 2's mean:
85.8°F - 85.1°F = 0.7°F
Therefore, the mean daily high temperature of the two samples differ by 0.7°F.
85.8°F - 85.1°F = 0.7°F
Therefore, the mean daily high temperature of the two samples differ by 0.7°F.
Bot, how did you get the mean sample 1 and sample 2
Sample 2 is 84.8