To find the surface area of the box, we need to find the area of each of the six faces and then sum them up.
1. The first face has dimensions 9 ft by 6 ft, so its area is 9 ft * 6 ft = 54 sq ft.
2. The second face has dimensions 6 ft by 6 ft, so its area is 6 ft * 6 ft = 36 sq ft.
3. The third face has dimensions 6 ft by 7 ft, so its area is 6 ft * 7 ft = 42 sq ft.
4. The fourth face is the same as the second face, so its area is also 36 sq ft.
5. The fifth face is the same as the third face, so its area is also 42 sq ft.
6. The sixth face has dimensions 7 ft by 9 ft, so its area is 7 ft * 9 ft = 63 sq ft.
Now, sum up all the areas:
54 sq ft + 36 sq ft + 42 sq ft + 36 sq ft + 42 sq ft + 63 sq ft = 273 sq ft
Therefore, the surface area of the box that Anthony decorates is 273 square feet.
Anthony is decorating the outside of a box in the shape of a right rectangular prism. The figure below shows a net for the box.
9 ft
6 ft
6 ft
7 ft
6 ft
6 ft
7f
What is the surface area of the box, in square feet, that Anthony decorates?
1 answer