each mole of HCl reacts with one mole of NaHCO3
so, how many moles of NaHCO3 do you have?
How many mL of 0.1M acid does that take?
Antacids are taken to relieve heartburn or indigestion caused by excess stomach acid. The active ingredients vary depending on the brand, but all contain bases. Each Alka-Seltzer(R) tablet contains 1.916 g of the active ingredient sodium bicarbonate (NaHCO3). When it dissolves, the sodium bicarbonate reacts with stomach acid (essentially 0.100 M HCl) according to the reaction below:
HCl(aq) + NaHCO3(aq) ----> NaCl(aq) + CO2(g) + H2O(l)
How many milliliters of stomach acid can one tablet of Alka-Seltzer(R) neutralize?
3 answers
1.916/84.008= 0.0228
but I'm not sure how to figure out how much it will neutralize
but I'm not sure how to figure out how much it will neutralize
mols NaHCO3 = 0.0228 = mols HCl
But M HCl = mols HCl/L HCl. You know M and mols, solve for L and convert to mL.
But M HCl = mols HCl/L HCl. You know M and mols, solve for L and convert to mL.