(answer this in simple words and grade 9 level) Please select any two variables (temperature, surface area, concentration and addition of a catalyst) to compare to the control experiment. You may describe the graph each produces and/or the number and behavior of particles of A, B, and C at the beginning and end of your test. For each of your choices, explain 'why' you think the rate of reaction changed with your adjustments. You may write your answer in paragraph or list form just be sure to tell me which two variable you select.

Question

6 points

(6 points)

Answer 1

I will compare temperature and concentration to the control experiment.

1. Temperature:

   • Beginning: When the temperature is low, the particles of A, B, and C move slowly and collide less often.
   • End: When the temperature is high, the particles move faster, collide more often, and react more quickly.
   • Graph: If we graph the reaction rate versus temperature, the line will show that as the temperature increases, the reaction rate also increases.
   • Why: The rate of reaction changed because higher temperatures give particles more energy, leading to more collisions and quicker reactions.

2. Concentration:

   • Beginning: In a diluted solution, there are fewer particles of A and B, so they collide less often.
   • End: When the concentration is high, there are more particles in the same space, leading to more collisions.
   • Graph: A graph of reaction rate versus concentration will show that as concentration increases, the reaction rate also increases.
   • Why: The rate of reaction changed because a higher concentration means more particles are available to react with each other, resulting in more collisions and faster reactions.

In summary, both higher temperature and concentration speed up the reaction because they increase the number of collisions between particles.