The given sequence is: \( 64, 32, 16, 8, 4, \ldots \)
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Is the sequence arithmetic or geometric?
- The sequence is geometric.
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Does it have a common difference or common ratio?
- It has a common ratio.
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What is the common difference or common ratio?
- The common ratio \( r \) can be calculated by dividing any term by the previous term:
- \( \frac{32}{64} = \frac{1}{2} \)
- \( \frac{16}{32} = \frac{1}{2} \)
- \( \frac{8}{16} = \frac{1}{2} \)
- \( \frac{4}{8} = \frac{1}{2} \)
- Thus, the common ratio is \( r = \frac{1}{2} \).
- The common ratio \( r \) can be calculated by dividing any term by the previous term:
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What are the next three terms?
- To find the next terms, we multiply the last term by the common ratio:
- \( 4 \times \frac{1}{2} = 2 \)
- \( 2 \times \frac{1}{2} = 1 \)
- \( 1 \times \frac{1}{2} = \frac{1}{2} \)
- Therefore, the next three terms are: \( 2, 1, \frac{1}{2} \).
- To find the next terms, we multiply the last term by the common ratio:
So, the complete answer is:
- The sequence is geometric.
- It has a common ratio of \( \frac{1}{2} \).
- The next three terms are \( 2, 1, \frac{1}{2} \).