look at the theoritical
molesO2=1/2 (massH2O2)/molmassH2O2)
massO2=molesO2*32
percent yeild=15/massO2above
Answer the question(s) below about the following reaction.
2H2O2 (l) → 2H2O(g) + O2(g)
If 50.0 grams hydrogen peroxide produce 15.0 g oxygen, what is the percent yield for this reaction?
2 answers
30
1 answer