Answer the following questions accurately

The linear function m = 50 - 9d represents the amount of m (in dollars) of your money you have left after buying d DVDs

a. Interpret the terms and coefficient in the equation
b. Find the domain of the function. Is the domain discrete or continuous?

9 answers

Sure! Let's break down the linear function \( m = 50 - 9d \) step by step.

a. Interpret the terms and coefficient in the equation

  • m: This represents the amount of money (in dollars) you have left after purchasing DVDs.
  • d: This is the number of DVDs you have bought.
  • 50: This is the initial amount of money you have (in dollars) before purchasing any DVDs.
  • -9: This is the coefficient of \( d \), representing the cost of each DVD. Specifically, it indicates that each DVD costs $9. As you buy more DVDs (increase \( d \)), your remaining money decreases by $9 for each additional DVD purchased.

b. Find the domain of the function. Is the domain discrete or continuous?

The domain of the function represents the valid values of \( d \) (the number of DVDs bought). In this context:

  • \( d \) cannot be negative because you cannot buy a negative number of DVDs.
  • The maximum number of DVDs you can buy occurs when \( m \) reaches zero (i.e., you spend all your money). To find the maximum \( d \), we can set \( m = 0 \) and solve for \( d \):

\[ 0 = 50 - 9d \ 9d = 50 \ d = \frac{50}{9} \approx 5.56 \]

Since you cannot buy a fraction of a DVD, the maximum whole number of DVDs you can buy is 5.

Thus, the domain of \( d \) in the context of this equation is:

\[ d \in {0, 1, 2, 3, 4, 5} \]

This shows that the values of \( d \) can only take on whole numbers from 0 to 5.

Is the domain discrete or continuous?

The domain is discrete because \( d \) can only take integer values (whole numbers) rather than every possible real number in the interval.

Simplify to just the answer, please.

a. Interpretation:

  • m: Money left (in dollars).
  • d: Number of DVDs bought.
  • 50: Initial money (in dollars).
  • -9: Cost per DVD (in dollars).

b. Domain: \( d \in {0, 1, 2, 3, 4, 5} \) (discrete).

Now if I were the graph it, what would be the points

To graph the function \( m = 50 - 9d \), you can find the points by substituting values for \( d \) (from 0 to 5) into the equation:

  1. \( d = 0 \): \( m = 50 - 9(0) = 50 \) → Point: \( (0, 50) \)
  2. \( d = 1 \): \( m = 50 - 9(1) = 41 \) → Point: \( (1, 41) \)
  3. \( d = 2 \): \( m = 50 - 9(2) = 32 \) → Point: \( (2, 32) \)
  4. \( d = 3 \): \( m = 50 - 9(3) = 23 \) → Point: \( (3, 23) \)
  5. \( d = 4 \): \( m = 50 - 9(4) = 14 \) → Point: \( (4, 14) \)
  6. \( d = 5 \): \( m = 50 - 9(5) = 5 \) → Point: \( (5, 5) \)

Points:

  • \( (0, 50) \)
  • \( (1, 41) \)
  • \( (2, 32) \)
  • \( (3, 23) \)
  • \( (4, 14) \)
  • \( (5, 5) \)
No, the points of the function using the domain

Apologies for the oversight. Here are the points of the function \( m = 50 - 9d \) based on the discrete domain \( d \in {0, 1, 2, 3, 4, 5} \):

  • For \( d = 0 \): \( m = 50 - 9(0) = 50 \) → Point: \( (0, 50) \)
  • For \( d = 1 \): \( m = 50 - 9(1) = 41 \) → Point: \( (1, 41) \)
  • For \( d = 2 \): \( m = 50 - 9(2) = 32 \) → Point: \( (2, 32) \)
  • For \( d = 3 \): \( m = 50 - 9(3) = 23 \) → Point: \( (3, 23) \)
  • For \( d = 4 \): \( m = 50 - 9(4) = 14 \) → Point: \( (4, 14) \)
  • For \( d = 5 \): \( m = 50 - 9(5) = 5 \) → Point: \( (5, 5) \)

Points based on the domain:

  • \( (0, 50) \)
  • \( (1, 41) \)
  • \( (2, 32) \)
  • \( (3, 23) \)
  • \( (4, 14) \)
  • \( (5, 5) \)
My grid is only 10x10. Graph the fiction using its domain.

Since the grid is only 10x10, we will only plot the points within that grid and limit our consideration to the maximum \(m\) value that fits within the constraints of the grid.

Given the points based on the original domain \( d \in {0, 1, 2, 3, 4, 5} \):

  1. \( (0, 50) \) - This point is outside the 10x10 grid.
  2. \( (1, 41) \) - This point is also outside the grid.
  3. \( (2, 32) \) - This point is outside the grid.
  4. \( (3, 23) \) - This point is outside the grid.
  5. \( (4, 14) \) - This point is outside the grid.
  6. \( (5, 5) \) - This point is within the grid.

Points on a 10x10 Grid:

Since all points except \( (5, 5) \) are outside the 10x10 grid range, the only point you can plot is:

  • \( (5, 5) \)

Summary:

  • The only point to graph on a 10x10 grid is \( (5, 5) \).