Answer the following questions about Fe(NO3)3.

Question

a. What is the mass percent of iron in this compound?
b. A different iron compound is 34.43% by mass iron. What mass of this compound is needed to get 125g of
pure iron?

Answer 1

You aren't telling me what you think. Do you know how to get percent? That's
%Fe = [(mass Fe/mass Fe(NO3)3]*100 = ? Use atomic masses and molar mass for mass.

For part b plug the numbers in part b into the equation I gave you for % and turn the crank.

Answer 2

thank you very much, if i am correct i think the answer for part b. should be approximately 363g?

Answer 3

You're right. Go to the head of the class.

Answer 4

thank you, I greatly appreciate your help.