answer the following for the given quadratic function.
f(x)=x^2+x^2-8
a. what is the vertex (h,k) of f?
(h,k)=? simplify your answer and type the answer in an ordered pair
b. what is the axis of symmetry?
9 answers
a. (0,-8) is the vertex
b. axis of symmetry is zero.
I have a feeling there is a typo.
Why would anybody have two like terms in the equation ?
should it be
f(x) = x^2 + 2x - 8 ????
Why would anybody have two like terms in the equation ?
should it be
f(x) = x^2 + 2x - 8 ????
Yes, Reiny you caught the typo
It should read f(x)=x^2+2x-8, thank you for catching that. So, now my answers will change that Riana gave. Right?
It should read f(x)=x^2+2x-8, thank you for catching that. So, now my answers will change that Riana gave. Right?
yes,
complete the square ....
f(x) = x^2 + 2x +1 - 1 -8
= (x+1)^2 - 9
vertex is (-1,-9)
axis of symmetry: x = -1 or x+1 = 0
complete the square ....
f(x) = x^2 + 2x +1 - 1 -8
= (x+1)^2 - 9
vertex is (-1,-9)
axis of symmetry: x = -1 or x+1 = 0
then your vertex is (-2,8)
and axis will be -1
and axis will be -1
the vertex can't be (-1,-9) its incorrect.
NO, check my reply
Yes it is !
http://www.wolframalpha.com/input/?i=plot+x%5E2+%2B+2x+-+8
http://www.wolframalpha.com/input/?i=plot+x%5E2+%2B+2x+-+8
1 answer