Ok so I know I have to convert the 88cm distance "d" in meters which comes out to 0.88m. The 18.4 degrees incremental rotation of the two disks to radians which comes out to 0.3211406 rad. The 634 rev/min rotational speed of the two disks comes out to 66.3587 rad/sec. I am stuck after that. If anyone can please help it would be greatly appreciated! Thanks!
The time "t" to traverse the distance "d" = .88m derives from t = rad/rad/sec.
The speed V of the bullet then derives from V = d/t = .88/t.
Answer in m/s.
The speed of a moving bullet can be determined by allowing the bullet to pass through two rotating paper disks mounted a distance 88 cm apart on the same axle. From the angular displacement 18.4 degrees of the two bullet holes in the disks and the rotational speed 634 rev/min of the disks, we can determinethe speed of the bullet.
What is the speed of the bullet? Answer in units of m/s.
Ok so I know I have to convert 88cm to meters which comes out to 0.88m, the 18.4 degrees to radians which comes out to 0.3211406 radians. 634 rev/min comes out to 66.3587 rad/s. I am stuck after that. If anyone can please help it would be greatly appreciated! Thanks!
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