Answer check please: Consider the circle (x-3)^2 + (y+1)^2 = 169. The point (15,4) is on the circle. Find an equation for the line that is tangent to the circle at this point. I got y= 5/12x-9/4.

Answer 1

C(3,-1), P(15,4).
m1 = (4+1) / (15-3) = 5/12.

m2 = -12/5 = Negative reciprocal 0f m1.

P(15,4).

Y = mx + b = 4.
(-12/5)15 + b = 4
-36 + b = 4
b = 40.

Eq: Y = (-12/5)x + 40.

Answer 2

what angle does an arc 6.6cm in length substend at the centre of a circle of radius 14cm if ^=22/7