Anne exerts a force of 34.1 N to pitch a softball. She moves the ball 1.8 meters before releasing it. What amount of work did Anne do on the ball?(1 point)

Question

Responses

18.9 J
18.9 J

32.3 J
32.3 J

61.38 J
61.38 J

35.9 J
35.9 J

Answer 1

To calculate the work done on the ball, you can use the formula for work:

\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]

In this case, since Anne is pitching the ball in the same direction as the force she applies, \(\theta\) is 0 degrees. The cosine of 0 degrees is 1.

Using the values provided:

• Force = 34.1 N
• Distance = 1.8 m

Now, calculate the work:

\[ \text{Work} = 34.1 , \text{N} \times 1.8 , \text{m} \times 1 \] \[ \text{Work} = 34.1 , \text{N} \times 1.8 , \text{m} = 61.38 , \text{J} \]

So, the amount of work Anne did on the ball is 61.38 J.