Anne exerts a force of 34.1 N to pitch a softball. She moves the ball 1.8 meters before releasing it. What amount of work did Anne do on the ball?(1 point)

Question

Responses

32.3 J
32.3 J

35.9 J
35.9 J

18.9 J
18.9 J

61.38 J

Answer 1

To calculate the work done, you can use the formula:

\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]

In this case, since Anne is applying the force in the same direction as the distance the ball is moved (assuming the angle θ is 0 degrees), the cosine of 0 degrees is 1. Therefore, the formula simplifies to:

\[ \text{Work} = \text{Force} \times \text{Distance} \]

Substituting the given values:

• Force = 34.1 N
• Distance = 1.8 m

\[ \text{Work} = 34.1 , \text{N} \times 1.8 , \text{m} \]

\[ \text{Work} = 61.38 , \text{J} \]

So, the amount of work Anne did on the ball is 61.38 J.