To count the number of outcomes in which E is not selected, we need to count the number of ways to select one letter from the remaining six letters, S, L, C, T, E, and D. There are six options for the first letter, so there are 6 ways to do this. Therefore, the probability that E is not selected is:
6/7 = 0.857 = 85.7%
Answer: $\frac{6}{7}$, 0.857, 85.7%
Anna mixes the letters S, E, L, E, C, T, E, and D thoroughly. Without looking, Mary draws one letter. Expressed as a fraction, decimal, and percentage, what is the probability that E will not be the letter Mary selects?
1 answer