Let's call aniline BNH2
...........BNH2 + HOH ==> BNH3^+ + OH^-
I..........0.201...........0........0
C...........-x.............x........x
E.........0.201-x..........x........x
Kb = (BNH3^+)(OH^-)/(BNH2)
You know x. Substitute into Kb expression and solve for Kb.
Aniline, C6H5NH2, is a weak base. If the hydroxide ion concentration of a 0.201 M solution is 9.2 10-6 M, what is the ionization constant for the base?
1 answer
1 answer