Anhydrous CuSO4 can be used to dry liquids in which it is insoluble. The CuSO4 is converted to CuSO4 x 5H20, which can be filtered off from the liquid. What is the minimum mass of anhydrous CuSO4 needed to remove 12.6 g H20 from a tankful of gasoline?

Answer 1

RMM of CuSO4=(63.55+32+4*16)=159.55
RMM of 5H2O = 5*(1*2+16)=90
Use proportions,
Amount of CuSO4 required
=12.6g *(RMM CuSO4)/(RMM 5H2O)
=?

Answer 2

1*2+16=18
5*18=90