To determine which community has the most children when both neighborhoods have the same number of households, we'll first calculate the average number of children per household for both Community A and Community B. Then, we can project that for 1,000 households in each community.
Community A:
| Number of Households | Total Number of Children |
|----------------------|-------------------------|
| 10 | 26 |
| 20 | 52 |
| 40 | 104 |
| 75 | 195 |
To find the average number of children per household in Community A:
- Average number of children per household = Total children / Number of households
- Using the last data point:
\[
\text{Average for A} = \frac{195 \text{ children}}{75 \text{ households}} = 2.6 \text{ children per household}
\]
Community B:
| Number of Households | Total Number of Children |
|----------------------|-------------------------|
| 12 | 30 |
| 24 | 60 |
| 50 | 125 |
| 85 | 212.5 |
To find the average number of children per household in Community B:
- Using the last data point:
\[
\text{Average for B} = \frac{212.5 \text{ children}}{85 \text{ households}} \approx 2.5 \text{ children per household}
\]
Comparison:
- Community A: 2.6 children per household
- Community B: 2.5 children per household
Children in 1,000 Households:
To estimate the total number of children for both communities with 1,000 households:
- For Community A:
\[
1,000 \text{ households} \times 2.6 \text{ children/household} = 2,600 \text{ children}
\]
- For Community B:
\[
1,000 \text{ households} \times 2.5 \text{ children/household} = 2,500 \text{ children}
\]
Conclusion:
Community A has the most children. There are 2,600 children in this community if there are 1,000 households.
Correct Response:
Community A has the most children. There are 2,600 children in this community if there are 1,000 households.
1 answer