Let's call the amount of water in the first bucket after pouring for t seconds "x" ml.
Since Andrea pours at a steady rate of 100 ml per second, the amount of water in the second bucket after pouring for t seconds is 100t ml.
We want the two buckets to have the same amount of water, so we can set up the equation:
x = 100t
We also know that the initial amount of water in the first bucket is 4800 ml, so x = 4800.
Substituting x = 4800 into the equation, we get:
4800 = 100t
Dividing both sides by 100, we find:
t = 4800 / 100 = 48.
Therefore, Andrea must pour for 48 seconds to get the same amount of water in each bucket. Answer: \boxed{48}.
Andrea is pouring water from a full bucket into an empty bucket.
The full bucket initially contained 4800 ml of water, and Andrea
pours at a steady rate of 100 ml per second. For how many seconds
must Andrea pour to get the same amount of water in each bucket?
1 answer