To analyze the linear function given with a slope of -3 that passes through the point (-2, 9), we can use the point-slope form of the equation of a line which is:
\[ y - y_1 = m(x - x_1) \]
Where:
- \( m \) is the slope,
- \( (x_1, y_1) \) is a point on the line.
Substituting the given values:
- \( m = -3 \)
- \( (x_1, y_1) = (-2, 9) \)
We get:
\[ y - 9 = -3(x + 2) \]
Now, simplifying this equation:
- Distribute the slope on the right side:
\[ y - 9 = -3x - 6 \]
- Add 9 to both sides:
\[ y = -3x - 6 + 9 \]
\[ y = -3x + 3 \]
Now that we have the equation in slope-intercept form (y = mx + b), we can more directly see that the equation is:
\[ y = -3x + 3 \]
Now let's look at the responses to find which matches:
- \( y = -2x - 3 \)
- \( y = -3x + 3 \)
- \( y = 3x - 3 \)
- \( y = -3x + 9 \)
The correct response that matches the derived linear function is:
\( y = -3x + 3 \).