analysis of a sample of an organic compound showed it to containd 39.9% of carbon,6.9% of hydrogen and 53.2% of oxygen.A,calculate it empirical formular.8,if its relative molecular mass,what is the molecuar formular of the compound.

Answer 1

If you take a 100 g sample you have 39.9 g C, 6.9 g H, and 53.2 g O.
mols C = 39.9/12 = ?
mols H = 6.9/1 = ?
mols O = 53.2/16 = ?
Now find the ratio of C to H to O in whole numbers with the smallest number being no less than 1. The easy way to do this is to divide the smallest number from above mols by itself. Divide the other numbers by that same small number. Your formula will be CxHyOz. This is the empirical formula. Find the empirical formula mass. Then empirical formula mass x a whole number = molar mass. You have the empirical formula mass and you have the molar mass (but you didn't give it in the post. Solve for the whole number. Post your work if you get stuck.

Answer 2

it's important

Answer 3

1/moles . 1moles .1moles