To find the height at which the pilot was flying, we can use the equation of motion:
h = vt + (1/2)at^2
Where:
h = height
v = initial velocity (3000 m/s)
t = time (in seconds)
a = acceleration (-9.8 m/s^2, downward acceleration due to gravity)
Plugging in the values, we get:
(a) For t = 300s:
h = (3000)(300) + (1/2)(-9.8)(300)^2
h = 900000 - 44100 = 855900 meters
(b) For t = 450s:
h = (3000)(450) + (1/2)(-9.8)(450)^2
h = 1350000 - 99000 = 1251000 meters
(c) For t = 500s:
h = (3000)(500) + (1/2)(-9.8)(500)^2
h = 1500000 - 122500 = 1377500 meters
(d) For t = 650s:
h = (3000)(650) + (1/2)(-9.8)(650)^2
h = 1950000 - 201850 = 1748150 meters
Therefore, the pilot was flying at a height of:
(a) 855900 meters at 300s, or
(b) 1251000 meters at 450s, or
(c) 1377500 meters at 500s, or
(d) 1748150 meters at 650s.
So the correct answer is not explicitly stated in the options - the height at 500s is 1377500m.
Anairforcepilotisflyinghorizontallyataspeedof3000m/sanddropsabombwhichhitsthe
target10slater.Atwhatheightwasthepilotflying?
(a)300s
(b)450s
(c)500s
(d)650s
1 answer