An urn contains 8black and

Question

7 green balls. Five balls are randomly drawn from the urn in succession, with replacement. That is, after each draw, the selected ball is returned to the urn. What is the probability that all
5balls drawn from the urn are green? Round your answer to three decimal places.

Answer 1

8 black and 7 green in urn (15 in all)
5 drawn with replacement.

Probability that first one is green:
P(1)=7/15
Probability that second one is green
P(2)=7/15
(ball is replaced)
...
P(5)=7/15
For all 5 steps to succeed, multiply together the individual probabilities
P(all five are green)
=(7/15)*(7/15)*(7/15)*(7/15)*(7/15)
=(7/15)^5
I will leave you to do the calculator part to evaluate to three decimal places.