An urn contains 14 white balls and 6 red balls. two balls are to be selected in succession, at random and without replacement what is the probability that i) both balls are white, ii) the first ball in white and the second ball is red, iii) one white ball and one red ball are selected, iv) would the probabilities change if the first ball after being identified is put back in the urn before the second ball is selected?

Answer 1

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

1) 14/20 * (14-1)/(20-1) = ?

2) 14/20 * 6/(20-1) = ?

3) Same as 2.

4) Yes, the total amount of balls would remain the same.