An urn A contains 6 white balls and 7 black balls. And urn B contains 8 white balls and 6 black balls. A person draws a ball at random from one of the two urns. It turns out to be black. What is probability that the ball was drawn from urn A?
(A) 7/14
(B) 49/88
(C) 39/88
(D) None of the above
2 answers
two urns contain white balls and yellow balls the first urn contains 10 white balls and 6 yellow balls and the second urn contains 8 white balls and 3 yellow balls a ball is drawn at random from each urn what is the probability that both balls are white
The probability of drawing a white ball from the first urn is 10/16 = 5/8, and the probability of drawing a white ball from the second urn is 8/11.
To find the probability of both events happening, we multiply the probabilities:
(5/8) × (8/11) = 40/88 = 5/11
Therefore, the probability of drawing two white balls is 5/11.
To find the probability of both events happening, we multiply the probabilities:
(5/8) × (8/11) = 40/88 = 5/11
Therefore, the probability of drawing two white balls is 5/11.
4 answers