the momentum components of the third particle will be eequal and opposite the components of the other two particles.
so the velocity components will be
V=x</b)(-7.4E-27/mass3 +y(-0E6)/5E-27)/mass3
where mass3 the mass of the third particle is 18E-27-5E27-7.4E-27
An unstable nucleus with a mass of 18.0 ✕ 10-27 kg initially at rest disintegrates into three particles. One of the particles, of mass 5.0 ✕ 10-27 kg, moves along the positive y-axis with a speed of 9.0 ✕ 106 m/s. Another particle, of mass 7.4 ✕ 10-27 kg, moves along the positive x-axis with a speed of 1.0 ✕ 106 m/s. (Assume that mass is conserved.)
What is the direction of motion?
in ° (from the positive x-axis)
1 answer