The M stands for the unknown element; it binds to the Bromine. Bromine has a -1 charge, and there are three, it is highly likely that the element is Aluminum or Boron.
27.765 g MBr3-2.809 g M=24.956 g 3Br-
24.956 g Br* (1 mol Br/239.7 g)=
.104 mol Br
This is the same number as that of M, so there are .104 mol M.
2.809 g M/.104 mol M=26.98 g/mol M.
This is the molar mass of aluminum.
An unknown element reacts with bromine to give bromide, MBr3. If 2.809g of the unknown element gives 27.765grams of MBr3, what is the element? ( give the symbol )
I don't understand the M in the MBr3...can someoen please help me with this question ASAP
thanks a lot
- i know this question was posted earlier but i did not understand something and bob did not reply to my question ( no prob , i understand you guys are busy but i really need help with this question, its worth a lot and im freaking out for the test tomm )
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