an unbiased coin is tossed six times. find the probability of the given event - the coin lands heads more than once.

Answer 1

must exclude no heads and 1 head
prob(no heads) = (1/2)^6 = 1/64
prob(1 head) = C(6,1) (1/2)^1 (1/2)^5 = 6/64

prob (more than 1 head) = 1 - 1/64 - 6/64
= 57/64

Answer 2

thank you so much, this helped alot