an thelet completes one round of circular track of diameter 200m in 40 secomds. wht will be the distance covered t the end of 2min & 20 s.

Answer 1

C= 3.14*D = 3.14 * 200M = 628m,

V = 628m / 40s = 15.7m/s,

t = 2min+20s = 120+20 = 140s.

d = Vt = 15.7m/s * 140s = 2198m.