C= 3.14*D = 3.14 * 200M = 628m,
V = 628m / 40s = 15.7m/s,
t = 2min+20s = 120+20 = 140s.
d = Vt = 15.7m/s * 140s = 2198m.
an thelet completes one round of circular track of diameter 200m in 40 secomds. wht will be the distance covered t the end of 2min & 20 s.
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