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An oxygen molecule consists of two oxygen atoms whose total mass is 5.3 x 10^-26 kg and whose moment of inertia about an axis p...Asked by Joe
An oxygen molecule consists of two oxygen atoms whose total mass is 5.3 x 10-26 kg and whose moment of inertia about an axis perpendicular to the line joining the two atoms, midway between them, is 1.82 × 10-46 kg·m2. From these data, estimate the effective distance between the atoms.
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Answered by
drwls
For each atom, more than 99.9% of the mass is in the nucleus, which can be treated as a point, when compared to the internuclear separation, d. Let M be the total mass of the molecule.
The moment of inertia of the O2 molecule, though an axis that passes midway between the atoms, is
I = 2*(M/2)*(d/2)^2 = M*d^2/4
= 1.82*10^-46 kg*m^2
d^2 = 7.28^10^-46/5.3*10^-26
= 13.74*10^-21 m^2
d = 1.172*10^-10 m = 1.172*10^-8 cm
= 1.172 Angstroms
The actual value is somewhat higher (1.21 Angstroms), but this is what the formula says.
The moment of inertia of the O2 molecule, though an axis that passes midway between the atoms, is
I = 2*(M/2)*(d/2)^2 = M*d^2/4
= 1.82*10^-46 kg*m^2
d^2 = 7.28^10^-46/5.3*10^-26
= 13.74*10^-21 m^2
d = 1.172*10^-10 m = 1.172*10^-8 cm
= 1.172 Angstroms
The actual value is somewhat higher (1.21 Angstroms), but this is what the formula says.
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