To find the vertex of the quadratic function \( h = -6t^2 - 24t + 20 \), we can use the vertex formula for a quadratic equation of the form \( at^2 + bt + c \), where the vertex \( t \) coordinate can be found using the formula:
\[ t = -\frac{b}{2a} \]
In this case, \( a = -6 \) and \( b = -24 \).
Plugging in the values:
\[ t = -\frac{-24}{2(-6)} = \frac{24}{-12} = -2 \]
Now we can find the \( h \) coordinate of the vertex by substituting \( t = -2 \) back into the equation:
\[ h = -6(-2)^2 - 24(-2) + 20 \]
Calculating step by step:
- \( (-2)^2 = 4 \)
- \( -6 \times 4 = -24 \)
- \( -24 \times -2 = 48 \)
- Adding: \( -24 + 48 + 20 = 44 \)
So, the vertex is \( (-2, 44) \).
Thus, the correct ordered pair representing the vertex is:
\[ \boxed{(-2, 44)} \]