To determine the vertex of the quadratic function \( h(t) = -6t^2 - 24t + 20 \), we can use the vertex formula for a parabola, which is given by
\[ t = -\frac{b}{2a} \]
where \( a \) and \( b \) are the coefficients from the standard form \( at^2 + bt + c \).
In this case:
- \( a = -6 \)
- \( b = -24 \)
Plugging these values into the formula gives:
\[ t = -\frac{-24}{2 \cdot -6} = \frac{24}{-12} = -2 \]
Now, we can find the height \( h \) at \( t = -2 \) by substituting it back into the original function:
\[ h(-2) = -6(-2)^2 - 24(-2) + 20 \] \[ = -6(4) + 48 + 20 \] \[ = -24 + 48 + 20 \] \[ = 24 \]
So the vertex of the parabola is at the point \( (-2, 24) \).
Therefore, the ordered pair that represents the vertex is:
(−2, 24).