To find the vertex of the function \( h(t) = -6t^2 - 24t + 20 \), we can use the vertex formula for a quadratic equation given in the form \( at^2 + bt + c \). The vertex \( t \)-coordinate can be found using:
\[ t = -\frac{b}{2a} \]
In this case, we have:
- \( a = -6 \)
- \( b = -24 \)
Substituting these values into the formula:
\[ t = -\frac{-24}{2 \cdot -6} \] \[ t = \frac{24}{-12} = -2 \]
Now we find the \( h \)-coordinate (the height) by substituting \( t = -2 \) back into the original equation:
\[ h(-2) = -6(-2)^2 - 24(-2) + 20 \] \[ = -6(4) + 48 + 20 \] \[ = -24 + 48 + 20 \] \[ = 24 \]
Thus, the vertex of the function is at the point \((-2, 24)\).
Now looking at the options provided, the correct ordered pair representing the vertex is:
(−2, 24)
So the correct response is:
\[ (-2, 24) \]