To find the vertex of the quadratic function given by \( h(t) = -6t^2 - 24t + 20 \), we can either complete the square or use the formula for the vertex of a parabola. The vertex \( (h, k) \) of a quadratic function in the standard form \( ax^2 + bx + c \) can be found using the formulas:
\[ t = -\frac{b}{2a} \] \[ h = f(t) \]
In this case, \( a = -6 \), \( b = -24 \), and \( c = 20 \).
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Calculate \( t \): \[ t = -\frac{-24}{2 \cdot -6} = \frac{24}{-12} = -2 \]
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Calculate \( h \) at \( t = -2 \): \[ h(-2) = -6(-2)^2 - 24(-2) + 20 \] \[ = -6(4) + 48 + 20 \] \[ = -24 + 48 + 20 \] \[ = 24 \]
So the vertex is at \( (-2, 24) \).
Therefore, none of the options in your list seem to represent the vertex correctly, but if we look closely, it seems like there might be a mistake in the available options. If "left parenthesis negative 2 comma 44 right parenthesis" is intended as \( (-2, 44) \), then that would be incorrect, as we found the vertex to be \( (-2, 24) \).
Thus, based on the calculations, the ordered pair representing the vertex is \( (-2, 24) \), which is not listed as one of the options you've provided. If you're limited to those choices, the calculations lead to \( (-2, 24) \) nonetheless.