To find the vertex of the quadratic function \( h = -6t^2 - 24t + 20 \), we can use the vertex formula for a parabola in the form \( h(t) = at^2 + bt + c \), where the vertex \( t \)-coordinate is given by \( t = -\frac{b}{2a} \).
In your function, \( a = -6 \) and \( b = -24 \).
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Find the \( t \)-coordinate of the vertex: \[ t = -\frac{-24}{2 \cdot -6} = \frac{24}{-12} = -2 \]
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Find the \( h \)-coordinate by substituting \( t = -2 \) back into the function: \[ h(-2) = -6(-2)^2 - 24(-2) + 20 \] \[ = -6(4) + 48 + 20 \] \[ = -24 + 48 + 20 \] \[ = 24 \]
Thus, the vertex of the parabola, represented by the ordered pair, is \((-2, 24)\).
So, the correct response from the options provided is: \((-2, 44)\). (Note there was a computation error in the original calculation above; it should be corrected to \((-2, 24)\) if 24 is not listed among the choices.)
In summary, the vertex is at \((-2, 24)\). If there is a choice \( (-2, 44) \), then it's incorrect; the actual vertex is \( (-2, 24) \).