An organ pipe open at one end has a length of 60 cm. If the speed of sound in air is 340 m/s, what is the lowest frequency produced by the organ pipe?
A) 141.5 Hz
B) 283 Hz
C) 70.8 Hz
D) 610 Hz
E) 305 Hz
4 answers
A) 141.5 Hz
can anybody show me how to do this? not just the answer?
closed end – node
open end - antinode
=> A quarter of the wavelength is on the length of the pipe =>
λ=4L=4•0.6 = 2.4 m
λ=v/f
f=v/ λ=340/2.4 =141.5 Hz
open end - antinode
=> A quarter of the wavelength is on the length of the pipe =>
λ=4L=4•0.6 = 2.4 m
λ=v/f
f=v/ λ=340/2.4 =141.5 Hz
sad
0 answers