an open box is to be made by cutting small congruent squares from corners of a 12cm by 12cm . sheet of tin and bending up the sides . how large should the squares cut from the corners to be make the box hold as much as possible ?

Answer 1

no

Answer 2

Let the Volume be V, and side of the square to be cut be x
V=x(12-x)^2
V=144x-48x^2+4x^3
dv/dx=144-96x+12x^2=0
12x^2-96x+144=0
x^2-8x+12=0
Solve for x
(x-2)(x-6)=0
x=2 0r x=6