An open box in form of a cuboid is made of wood 0.5cm thick. The exterbal diameter of the box are: lenth=51cm,width=45cm depth =21cm

Find the area of the volume of wood

1 answer

To find the volume of the wood used to make the open box, we first need to calculate the volume of the external dimensions and then the internal dimensions.

Step 1: Calculate the external volume

The external dimensions of the box are:

  • Length \( L_{\text{external}} = 51 , \text{cm} \)
  • Width \( W_{\text{external}} = 45 , \text{cm} \)
  • Height \( H_{\text{external}} = 21 , \text{cm} \)

The external volume \( V_{\text{external}} \) can be calculated using the formula for the volume of a cuboid:

\[ V_{\text{external}} = L_{\text{external}} \times W_{\text{external}} \times H_{\text{external}} \]

Plugging in the values:

\[ V_{\text{external}} = 51 \times 45 \times 21 \]

Calculating this:

\[ V_{\text{external}} = 51 \times 45 = 2295 , \text{cm}^2 \] \[ V_{\text{external}} = 2295 \times 21 = 48195 , \text{cm}^3 \]

Step 2: Calculate the internal volume

The thickness of the wood is 0.5 cm. We need to subtract twice the thickness from each dimension to find the internal dimensions.

  • Length \( L_{\text{internal}} = L_{\text{external}} - 2 \times 0.5 = 51 - 1 = 50 , \text{cm} \)
  • Width \( W_{\text{internal}} = W_{\text{external}} - 2 \times 0.5 = 45 - 1 = 44 , \text{cm} \)
  • Height \( H_{\text{internal}} = H_{\text{external}} - 0.5 = 21 - 0.5 = 20.5 , \text{cm} \)

Now we calculate the internal volume \( V_{\text{internal}} \):

\[ V_{\text{internal}} = L_{\text{internal}} \times W_{\text{internal}} \times H_{\text{internal}} \]

Plugging in the values:

\[ V_{\text{internal}} = 50 \times 44 \times 20.5 \]

Calculating this:

\[ V_{\text{internal}} = 50 \times 44 = 2200 , \text{cm}^2 \] \[ V_{\text{internal}} = 2200 \times 20.5 = 45100 , \text{cm}^3 \]

Step 3: Calculate the volume of the wood

The volume of the wood \( V_{\text{wood}} \) is the difference between the external volume and the internal volume:

\[ V_{\text{wood}} = V_{\text{external}} - V_{\text{internal}} \] \[ V_{\text{wood}} = 48195 - 45100 = 3005 , \text{cm}^3 \]

Conclusion

The volume of the wood used to make the open box is 3005 cm³.