Ask a New Question

An Olympic long jumper is capable of jumping 8.44m. Assuming his horizontal speed is 5.644m/s as he leaves the ground, how high does he go?

1 answer

time in air:
distance=vh*time
time= 8.44/5.644 sec

so max heigh give a falling time 1/2 time in air.

hf=hmax-1/2 *9.8*(1/2*8.44/5.644)^2
hf=0, solve for hmax

Ask a New Question or answer this question.

Similar Questions

an olympic long jumper i capable of jumping 8.0 m. Assuming hi horizonal speed is 9.1 m/s as he leaves the ground, how long is
1. 1 answer
An Olympic long jumper leaves the ground at an angle of 23 degrees and travels through the air for a horizontal distance of 8.7
1. 3 answers
A long jumper leaves the ground with an initial velocity of 12 m/s at an angleof 28°above the horizontal. Determine the peak
1. 1 answer
A smoke jumper jumps from a plane that is 1800 ft above the ground. The function h=-16^2 + 1800 gives the jumper's height h in
1. 1 answer

more similar questions