Dx = Xo*t = 7.5 m.
8.8 * t = 7.5.
t = 0.852 s.
h = 0.5g*t^2.
g = 9.8 m/s^2.
t = 0.852 s.
h = ?.
An Olympic long jumper is capable of jumping 7.5 m. Assume that his horizontal speed is 8.8 m/s as he leaves the ground.
How long is he in the air?
How high does he go? Assume that he lands standing upright, that is, the same way he left the ground.
1 answer
1 answer