Let x be the base length and y be the height of sail C.
The area of sail A is (1/2)*6*8 = 24 square meters.
According to the problem, the area of sail C is less than twice the area of sail A, so we have:
(1/2)*x*y < 2*24
or
x*y < 96
We don't have enough information to solve for x and y exactly, but we can find possible solutions that satisfy the above inequality. For example, x=12 and y=8 would work, because:
(1/2)*12*8 = 48 = 2*24
But there are many other possible solutions, such as x=16 and y=6, x=8 and y=12, etc.
In any case, the base length and height of sail C are not uniquely determined by the given information, but we know that its area is less than twice the area of sail A.
An old sailing ship has 4 triangular sails, sail A, sail B, and sail C. Sail A is the smallest of the sails, sail A measures 6m along the base, and 8m in height. Sail C is the largest of the sails, sail C has an area less than twice the area of sail A. Answer for the base length, height and area of sail C.
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