You did everything right. You just need to change the sign at the end. so your answer should be +0.1045
Hope this helps :)
An old car is traveling down a long, straight, dry road at 25.0 m/s when the driver slams on the brakes, locking the wheels. The car comes to a complete stop after sliding 305 m in a straight line. If the car has a mass of 755 kg, what is the coefficient of kinetic friction between the tires and the road?
vi= 25 m/s
vf=0
x=305
I used vf^2= vi^2+2ax
0=(25^2)+2a(305)
0=625+ 610 a
a=-625/610
a= -1.025 m/(s^2)
mu(k)= a/g
mu(k)= -1.025/9.8
mu(k)= -.1045
I put this in as an answer and it said I was wrong. Can anyone tell me what I'm doing wrong? Or possibly a different way to go about the problem? Help is much appreciated!
1 answer
3 answers