An old bottle of 12.3 M hydrochloric acid has only 33 mL left in it. What is the HCl concentration if enough water is added so that the final volume is 513 mL?

Answer 1

calculate the number of millimoles in the original

12.3 x 33 mmoles

the final volume is 513 ml so the concentration (moles per litre) is

12.3 x 33 mmoles/513 ml